+738 hi qwertyzz,
Since we know \(\overline{CD}\) and \(\overline{DA}\) are congruent and \(\angle {ADC} \text{ is } 60^{\circ}\), that means \(\triangle{ADC}\) is an equilateral triangle. Because it's an equilateral triangle, that means all sides of \(\triangle{ADC}\) are congruent. So, \(\overline{AC}\) is also \(\boxed{17}\).
I hope this helped you!
Let me know if you don't understand anything!
:)
+738 hi qwertyzz,
Since we know \(\overline{CD}\) and \(\overline{DA}\) are congruent and \(\angle {ADC} \text{ is } 60^{\circ}\), that means \(\triangle{ADC}\) is an equilateral triangle. Because it's an equilateral triangle, that means all sides of \(\triangle{ADC}\) are congruent. So, \(\overline{AC}\) is also \(\boxed{17}\).
I hope this helped you!
Let me know if you don't understand anything!
:)
Please show how you got your answer so I can learn from it.
