Draw a line perpendicular to the line that contains the points
(1, 6) and (4, 4) and passes through the point (−2, 6).
Can't seem to figure out how to do the numbers by drawing a perpendicular line
+6252 ok two steps to this
first we find the slope of the line passing through the two points
m=4−14−6=−32
now we want a line perpendicular to this so we have a slope of
m⊥=−1m=−(1−32)=23
now using point slope formula with the point (-2,6) we have
(y−6)=23(x−(−2))y=23x+223
