Can someone do this?

To see heureka's answer more clearly....note that he wrote 666 in terms of base 2, i.e., 2^x = 666

And "x" = ln666/ ln2  = 9.3793783670712621

So, we have

2^19112000 / 666 =

2^19112000/ 2^{9.3793783670712621}  =

2 ^{(19112000-9.3793783670712621)} =

2^{19111990.6206216329287379}

Still.....a pretty large number !!!

If you know someone who uses the linux operating system on their computer, ask them to run this short program and to mail you the results. You can then go over it and count the number of occurrences!

Here's the prgram: dc '2 19112000^f'

Happy counting!

Can someone do this? $${{\mathtt{2}}}^{{\mathtt{19\,112\,000}}}$$  If you can ca you tell me how many 666 are in the number

There are   $$\left{\downarrow}\ 2^{\left(19112000-\frac{\ln{666}}{\ln{2}} \right) }\right{\downarrow}$$  666 numbers

$$\\=\left{\downarrow}\ 2^{(19112000-9.379378373) }\right{\downarrow}\\ =\left{\downarrow}\ 2^{19111990.620621627}\right{\downarrow}$$