What non-zero integer must be placed in the square so that the simplified product of these two binomials is a binomial: (3x+1)(12x−◻)?
+592 If we need a binomial, then that means we need only 2 terms. One being 36x2, and the other being an integer. This means we have to cancel out the terms with a variable of x.
Lets let the missing integer be y:
(3x+1)(12x−y)=36x2−3xy+12x−y
We just need to find an integer y such that −3xy+12x=0 We can divide both sides by -3 and we see that y has to equal 4
