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Beng, Chandra and Danial have some stickers. Chandra and Danial have 7/10 of the stickers. Beng and Danial have 6/7 of the stickers. Beng and Chandra have a total of 620 stickers. How many more stickers did Danial collect than Beng?

 Feb 11, 2015

Best Answer 

 #7
avatar+130466 
+5

I'm just doing this one to see if I can solve it without "cheating" and looking at other's answers.....!!!

Let N be the total number of stamps....so we have

C + D   = 49/70N   (1)

B + D  = 60/70N    (2)

B + C = 620

Adding (1) and(2), we have

620 + 2D  = (109/70)N  → D = (109/140)N - 310

So

B + C + D  = N

620 + (109/140)N - 310  = N

310 = (31/140)N →   N = 1400

So D has  (109/140)(1400) - 310 = 780

And B has

780 +  = (6/7)(1400) → D = 1200 - 780 = 420

So D - B = 780 - 420 = 360 more

 

 Feb 11, 2015
 #1
avatar+33654 
+5

Using an obvious notation we have:

Sticker numbers

.

 Feb 11, 2015
 #2
avatar
+5

Beng and Danial have 6/7 of the stickers ,so chandra have 1/7 of the total stickers

so Danial have 7/10-1/7=39/70 of the total stickers , so beng have 6/7-39/70=21/70=3/10

Beng and chandra have 1/7+3/10=31/70,so the Danial ,Beng and chandra have 620/31*70=1400

Danial collect  more 1400*(39/70-3/10)=1400*(9/70)=180 stickers than Beng

 Feb 11, 2015
 #3
avatar+118703 
0

I think we need an adjudicator on this one - I don't have time at present   

Thank you   :))

 Feb 11, 2015
 #4
avatar
+5

i made a mistook.

39/70-3/10=39/70-21/70=18/70

(18/70)*1400=360 ,so Danial collect more 360 than Beng.

i am so sorry guys.

 Feb 11, 2015
 #5
avatar+26396 
+5

Beng, Chandra and Danial have some stickers. Chandra and Danial have 7/10 of the stickers. Beng and Danial have 6/7 of the stickers. Beng and Chandra have a total of 620 stickers. How many more stickers did Danial collect than Beng

 All Stickers =x (1)b+c+d=xc+d=xbb+d=xcb+c=xd(2)c+d=710x710x=xb(3)b+d=67x67x=xc(4)b+c=620620=xdb+c+d=xb=310xc=17xd=x620310x+17x+x620=xx=1400

b=3101400=420c=171400=200d=1400620=780db=780420=360

How many more stickers did Danial collect than Beng?  360

 Feb 11, 2015
 #6
avatar+118703 
0

Thank you Heureka and Alan 

 

We all make mistakes anon.  Don't sweat it 

 Feb 11, 2015
 #7
avatar+130466 
+5
Best Answer

I'm just doing this one to see if I can solve it without "cheating" and looking at other's answers.....!!!

Let N be the total number of stamps....so we have

C + D   = 49/70N   (1)

B + D  = 60/70N    (2)

B + C = 620

Adding (1) and(2), we have

620 + 2D  = (109/70)N  → D = (109/140)N - 310

So

B + C + D  = N

620 + (109/140)N - 310  = N

310 = (31/140)N →   N = 1400

So D has  (109/140)(1400) - 310 = 780

And B has

780 +  = (6/7)(1400) → D = 1200 - 780 = 420

So D - B = 780 - 420 = 360 more

 

CPhill Feb 11, 2015
 #8
avatar+130466 
0

Yep..that looks correct.....I love these "Brain Teasers".....!!!

 

 Feb 11, 2015

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