Arithmetic of Complex Numbers

Hi Cupcake,

To answer this question you just need to recognise that 

\(n(cos\theta+isin\theta)=ne^{\theta i}\)

Convert them both to this form,

do the division

 then convert the answer back to the original form.   

Do you understand cupcake?  Have you figured out the answer yet?

\(\frac{5e^{\frac{\pi}{2}i}}{2e^{\frac{5\pi}{6}i}}\\~\\ =\frac{5}{2}e^{ (\frac{\pi}{2}-\frac{5\pi}{6}) i }\\~\\ =\frac{5}{2}e^{ (\frac{-2\pi}{6}) i }\\~\\ =\frac{5}{2}e^{ (\frac{-\pi}{3}) i }\\~\\ =\frac{5}{2}(cos(\frac{-\pi}{3})+isin(\frac{-\pi}{3})) \)