Any quick methods to solve?

Question: Compute

$\dfrac{5}{4 \cdot 9} + \dfrac{7}{9 \cdot 16} + \dfrac{9}{16 \cdot 25} + \dfrac{11}{25 \cdot 36}$

$\begin{array}{|rcll|} \hline && \mathbf{\dfrac{5}{4 \cdot 9} + \dfrac{7}{9 \cdot 16} + \dfrac{9}{16 \cdot 25} + \dfrac{11}{25 \cdot 36}} \\\\ &=& \dfrac{5}{9 \cdot 4} + \dfrac{7}{16 \cdot 9} + \dfrac{9}{25 \cdot 16} + \dfrac{11}{36 \cdot 25} \\\\ &=& \dfrac{9-4}{9 \cdot 4} + \dfrac{16-9}{16 \cdot 9} + \dfrac{25-16}{25 \cdot 16} + \dfrac{36-25}{36 \cdot 25} \\\\ &=&\small{ \dfrac{9}{9 \cdot 4} -\dfrac{4}{9 \cdot 4} + \dfrac{16}{16 \cdot 9} -\dfrac{9}{16 \cdot 9} + \dfrac{25}{25 \cdot 16} -\dfrac{16}{25 \cdot 16} + \dfrac{36}{36 \cdot 25} -\dfrac{25}{36 \cdot 25}} \\\\ &=& \dfrac{1}{4} -\dfrac{1}{9} + \dfrac{1}{9} -\dfrac{1}{16} + \dfrac{1}{16} -\dfrac{1}{25} + \dfrac{1}{25} -\dfrac{1}{36} \\\\ &=& \dfrac{1}{4} -\dfrac{1}{36} \\\\ &=& \dfrac{36-4}{4*36} \\\\ &=& \dfrac{32}{4*36} \\\\ &=& \dfrac{8}{36} \\\\ &=& \mathbf{\dfrac{2}{9}} \\ \hline \end{array}$

$\dfrac{5}{4 \cdot 9} + \dfrac{7}{9 \cdot 16} + \dfrac{9}{16 \cdot 25} + \dfrac{11}{25 \cdot 36} = \mathbf{\dfrac{2}{9}}$