Another confusing problem

Question

Another confusing problem

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Find the sum of the first 9 terms in the following geometric series.
Do not round your answer.

64+32+16+...

I'm writing this one out but I got confused after:

64+32+16+8+4+2+???????????

EDIT:

I kind of figured it out....

is it 64+32+16+8+4+2+1+1/2+1/4?

then its:

127.75 right?

tommarvoloriddle Aug 6, 2019

edited by tommarvoloriddle Aug 6, 2019

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Rom · Answer 1 · 2019-08-06T03:05:57

$\text{I guess the series they are after has $a=64,~r=\dfrac 1 2$}\\ 64 \sum \limits_{k=0}^8\left(\dfrac 1 2 \right)^k = 64 \dfrac{1-\left(\frac 1 2 \right)^9}{1 - \frac 1 2} = \\ 64 \dfrac{1 - \frac{1}{512}}{\frac 1 2} = \dfrac{511}{4}=127.75\\ \text{Well done!}$

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Another confusing problem

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