+1556 Let $M$, $N$, and $P$ be the midpoints of sides $\overline{TU}$, $\overline{US}$, and $\overline{ST}$ of triangle $STU$, respectively. Let $\overline{UZ}$ be an altitude of the triangle. If $\angle TSU = 62^\circ$ and $\angle STU = 29^\circ$, then what is $\angle TMP + \angle TUZ$ in degrees?
+410 
∵△TSU∼△TPM
∴∠TMP=∠TUS=89∘
∵∠STU=29∘,∠TZU=90∘
∴∠TUZ=180−29−90=61∘
∴∠TMZ+∠TUZ=160∘.
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