Analytic Geometry

Question

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The area of rectangle ABCD with vertices A(0, 0), B(0, 4), C(x, 4) and D(x, 0) is $16$ square units. If x > 0, what is the value of x?

Guest Apr 13, 2022

Vinculum · Answer 1 · 2022-04-13T07:17:06

From the information given above, we can say that the width of the rectangle is $4$

The area of a rectangle is $length \cdot width$

That is, $4 \cdot length = 16$

That gives us length = $16/4 = 4$

From that, we can tell that the value of $x$ must be $4$ .

Kakashi · Answer 2 · 2022-04-13T07:22:23

Yes i think so

CPhill · Answer 3 · 2022-04-13T07:50:30

Note that a square is a special case of a rectangle....but a rectangle isn't necessarily a square

Since AB = 4 ....then it must also be that BC = 4

So....the area = (AB) (BC) = (4)(4) = 16

Kakashi · Answer 4 · 2022-04-13T07:56:54

Good Job vin