Find the conic section represented by the equation
4x^2 - 8y^2 - 28x + 49 = 4x^2 + 5x - 11y + 20
Simplify as
-33x -8y^2 + 11y + 29 = 0
33x + 8y^2 - 11y - 29 = 0
33x = -8y^2 + 11y + 29
x = (-8y^2 + 11y + 29) / 33
x to 1st power, y to second power = negative in front of y^2 = parabola opening to the left
+290 
