When g(x) is divided by x^2 - x - 6, the remainder is 2x + 7. What is the value of g(8)?
Let g(x) = x^3 + bx^2 + cx + d
x
x^2 - x - 6 [ x^3 + bx^2 + cx + d ]
x^3 - x^2 - 6x
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b + 1 = 0 c + 6 = 2 d = 7
b = -1 c = -4
So g(x) = x^3 -x^2 -4x + 7
g(8) = 8^3 - 8^2 - 4(8) + 7 = 423
+290 
