+1518 Three runners, Dirk, Edith, and Foley all start at the same time for a $24$ km race, and each of them runs at a constant speed. When Dirk finishes the race, Edith is $10$ km behind, and Foley is $15$ km behind. When Edith finishes the race, how far behind is Foley, in km?
+1950 When Dirk finishes, Edith has run 14km and Foley has run 9 km
This means that Foley runs 9/14 as fast as Edith
When Edith has run 24km, Foley has run 24(9/14)≈15.43km
So Foley is 24−15.43≈8.57 km behind!
Thanks! :)
