algebra

algebra
Define
$a@b = ab - b^2$ and
$a\#b = a + b - ab$.
What is $(6@2)/(6\#2)$?

$\begin{array}{|rcll|} \hline (6@2)/(6\#2) &=& \dfrac{6@2}{6\#2)} \\\\ (6@2)/(6\#2) &=& \dfrac{6*2-2^2}{6+2-6*2} \\\\ (6@2)/(6\#2) &=& \dfrac{12-4}{8-12} \\\\ (6@2)/(6\#2) &=& \dfrac{8}{-4} \\\\ \mathbf{(6@2)/(6\#2)} &=& \mathbf{-2} \\ \hline \end{array}$