Let r and s be the roots of 3x^2 + 4x + 12 = 2x^2 - 7x + 5. Find r^2 + s^2.
Let r and s be the roots of 3x2+4x+12=2x2−7x+5.Find r2+s2.
3x2+4x+12=2x2−7x+53x2−2x2+4x+7x+12−5=0x2+11x+7=0
Vieta: rs=7, −(r+s)=11
−(r+s)=11r+s=−11(r+s)2=(−11)2r2+2rs+s2=121|rs=7r2+2∗7+s2=121r2+s2=121−14r2+s2=107