Algebra

1. \(a+b+c=-3\)

2. \(a+3b+c=9\)

3. \(a+b+3c=-19\)

Subsrtacting equation number 1 from equation number 2 we get

\(b=6\)

Substracting equation number 1 from equation number 3 we get

\(c=-8\)

Then putting \(b\) and \(c\) into equation 1

we get

\(a=-1\)

so

\(abc=-1\times-8\times6=\)48

Very nice, FMP    !!!!!!