Algebra

Let's set some variables and make some observations. 

Let's let $d = a_2 -a_1$

Now, let's note something important. Note that

$S_5 = 5a_1 + (d + 2d + 3d + 4d) = 5a_1 + 10d\\ S_{10} = 10a_1 + (d + 2d + \cdots + 9d) = 10a_1 + 45d\\ S_{15} = 15a_1 + (d + 2d + \cdots + 14d) = 15a_1 + 105d$

These observations are really important for us to solve the problem. 

Let's take two of these cases. We can write a system of equations, and we get

$\begin{cases} 5a_1 + 10d = \dfrac15\\ 10a_1 + 45d = \dfrac1{10} \end{cases}$

Now, we solve for a1 and d. 

Solving this system of equations, we get

$d = -\dfrac3{250}\\ a_1 = \dfrac8{125}$

Plugging this into S15, we get $S_{15} = 15a_1 + 105d = -\dfrac3{10}$

So -3/10 is our final answer. 

Thanks! :)