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Levans writes a positive fraction in which the numerator and denominator are integers, and the numerator is 2 greater than the denominator. He then writes several more fractions. To make each new fraction, he increases both the numerator and the denominator of the previous fraction by 1. He then multiplies all his fractions together. He has 3 fractions, and their product equals 10. What is the value of the first fraction he wrote?

 Feb 12, 2025

Best Answer 

 #1
avatar+1376 
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(x+2)/(x)  •  (x+3)/(x+1)  •  (x+4)/(x+2)  =  10    

 

cancel the (x+2) ' s   

 

(1)/(x) • (x+3)/(x+1) • (x+4)/(1) = 10    

 

[ (1) • (x+3) • (x+4) ] / (x) • (x+1) • (1) ] = 10    

 

(x2 + 7x + 12) / (x2 + x) = 10    

 

x2 + 7x + 12 = 10x2 + 10x    

 

0 = 9x2 + 3x – 12     this will factor    

 

(3x + 4) • (3x – 3) = 0    

 

                      3x + 4 = 0     this x will not be an integer, so disregard    

 

                      3x – 3 = 0    

                            3x = 3    

                              x = 1     therefore (x+2) / (x) = 3/1 = 3 is the value of the first fraction   

.    

 Feb 12, 2025
 #1
avatar+1376 
+1
Best Answer

 

(x+2)/(x)  •  (x+3)/(x+1)  •  (x+4)/(x+2)  =  10    

 

cancel the (x+2) ' s   

 

(1)/(x) • (x+3)/(x+1) • (x+4)/(1) = 10    

 

[ (1) • (x+3) • (x+4) ] / (x) • (x+1) • (1) ] = 10    

 

(x2 + 7x + 12) / (x2 + x) = 10    

 

x2 + 7x + 12 = 10x2 + 10x    

 

0 = 9x2 + 3x – 12     this will factor    

 

(3x + 4) • (3x – 3) = 0    

 

                      3x + 4 = 0     this x will not be an integer, so disregard    

 

                      3x – 3 = 0    

                            3x = 3    

                              x = 1     therefore (x+2) / (x) = 3/1 = 3 is the value of the first fraction   

.    

Bosco Feb 12, 2025

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