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avatar+766 

Find all real numbers a and b such that

a + b = 14

a^3 + b^3 = 812 + a^2 + b^2

 
 Mar 8, 2025
 #1
avatar+6 
+1

Couldn't you just substitute a=-14-b into the second equation and then factor/solve the cubic?

 Mar 8, 2025
 #2
avatar+130458 
+1

a + b  = 14

b = 14  - a

 

a^3  + (14 -a)^3  = 812 + a^2 + (14 -a)^2

 

a^3  - a^3 + 42a^2 -588a + 2744  = 812 + a^2 + a^2 - 28a + 196

 

40a^2  - 560a + 1736  =  0 

 

5a^2  -  70a + 217  =  0

 

a  =  [  70  +  sqrt  [  70^2  - 20*217] ] / 10   =  [ 70 + sqrt [ 15260] ] / 10  =  [ 70 + 2sqrt 35 ] / 10  =

 

7 +  sqrt (35) / 5

 

And  b =  7 - sqrt(35) / 5

 

Also   a =  7 - sqrt (35) / 5     and b = 7 + sqrt (35)   / 5

 

 

cool cool cool

 Mar 11, 2025

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