+216 Three runners, Dirk, Edith, and Foley all start at the same time for a $24$ km race, and each of them runs at a constant speed. When Dirk finishes the race, Edith is $10$ km behind, and Foley is $15$ km behind. When Edith finishes the race, how far behind is Foley, in km?
+1952 After Dirk finally finishes the race, Edith has ran 14 km while Foley has ran 9 km.
This essentially means that Foley is 9/14 as fast as Edith.
This means when Edith has ran 24 km, Foley has ran 24(9/14)≈15.43 km.
So Foley is 24−15.43≈8.57km behind Edith!
Thanks! :)
+1952 After Dirk finally finishes the race, Edith has ran 14 km while Foley has ran 9 km.
This essentially means that Foley is 9/14 as fast as Edith.
This means when Edith has ran 24 km, Foley has ran 24(9/14)≈15.43 km.
So Foley is 24−15.43≈8.57km behind Edith!
Thanks! :)
