Algebra

First, let's combine all like terms on the right side of the equation. 

We get the formula

$y=-5x^{2}-6x+10$

Now, it's important to note that the x coordinate of the vertex can be written in the form

$\frac{-b}{2a}$ for parabolas in the form of $y=ax^2+bx+c$

Thus plugging in -5 and -6, we get

$x=6/-10 = -3/5=-0.6$

Plugging this back into the equation, we fins that $y=11.8$

Thus the vertex is at $(-0.6, 11.8)$

So our answer is $(-0.6, 11.8)$

Thanks! :)