1.
What is the solution to the inequality?
4(2x+5)−2x≥10
Enter your answer in the box.
+486 $4(2x+5)-2x=8x+20-2x=6x+20$.
Now the inequality is:
$6x+20>=10$
$6x>=-10$
$x>=-6$
Or, in interval notation: $\boxed{[-6, \infty)}$
Thank you but the correct answer is x≥-5/3.
I did the same thing you did, so i thought that was the correct answer as well. Apparently not. Thanks a lot though. c:
+486 Oh my god, thank you so much, I just realized where I went wrong. I had a brain freeze, on the last step, where I divide by 6, you get $x>=\frac{-10}{6}=\frac{-5}{3}$, not $x>=-6$. I'm really sorry.
+373 Hey there, Guest!
Let's solve your inequality step-by-step.
\(4(2x+5)−2x≥10\)
Step 1: Simplify both sides of the inequality.
\(6x+20≥10\)
Step 2: Subtract 20 from both sides.
\(6x+20−20≥10−20\)
\(6x≥−10\)
Step 3: Divide both sides by 6.
\(\frac{6x}{6}\)\(≥\)\(\frac{-10}{6}\)
Therefore, your answer is \(x≥ \frac{-5}{3}\).
Hope this helped! :)
( ﾟдﾟ)つ Bye
