Algebra

To make the equation clear, it looks like this: ${y\over3}+1={y+3\over y}+7$.

Then multiply every term by '3y'.

It should now look like this:$y^2 + 3y = 3y + 9 + 21y$.

Combining like terms and moving the equation to one side, we get: $y^2 - 21y - 9 = 0$.

Then you can use the quadratic formula $x = {-b \pm \sqrt{b^2-4ac} \over 2a}$ where a is the coefficient of x^2. b is the coefficient of x, and c is the constant.

Plugging in the values, we have:

$y = {21 + 3\sqrt{53}\over2}$

$y = {21-3\sqrt{53}\over2}$

Those are the two possible values of y :)