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For parts (a) through (d), let f(x) = 2x^2 - 13x + 20 - 5x^2 + 19x + 7.

 

What is the vertex of the parabola y = f(x)?

 
 Mar 30, 2025
 #1
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First, we can simplify f(x): f(x)=3x2+6x+27. Then, we factor out -3 for f(x)=3(x22x9)=3(x1)2+30.

 From this equation, we get that the vertex of f(x) is (x, y) = (1, 30).

 Mar 30, 2025

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