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Given the hyperbola (y2/16) – (x2/9) = 1, find the equations for its asymptotes.
 Mar 18, 2014
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Since your hyperbola has the "y" term listed first, it opens "up and down.'

It's also centered at (0,0)

So the form is: y^2/b^2 - x^2/a^2 = 1

In your case, b^2 = 16, so b = SQRT(16) = 4 and a^2 = 9, so, a = SQRT(9) = 3

So, the equations for the asymptotes are y = +(b/a)x and y = -(b/a)x

So we have, in your case .....y = +(4/3)x and y = -(4/3)x

And there you are!!
 Mar 18, 2014

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