a^b=b where a and b are different numbers

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Guest Apr 22, 2014

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a^b=b where a and b are different numbers

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Let a = √(2) .....let b = 2

Then....... (√(2))² = 2

Note that a, b ARE "different," since √(2) ≠ 2

(You didn't specify that "a" had to be an integer, only a "number"!!)

CPhill Apr 22, 2014

CPhill · Answer 1 · 2014-04-22T11:42:04

a^b=b where a and b are different numbers

-----------------------------------------------------------------------------------------------------------------------------

Let a = √(2) .....let b = 2

Then....... (√(2))² = 2

Note that a, b ARE "different," since √(2) ≠ 2

(You didn't specify that "a" had to be an integer, only a "number"!!)