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a3+b3

 Sep 17, 2015

Best Answer 

 #1
avatar+26396 
+5

a3+b3= ?

 

 

 

(a+b)3=a3+3a2b+3ab2+b3(a+b)33a2b3ab2=a3+b3(a+b)33ab(a+b)=a3+b3(a+b)[(a+b)23ab]=a3+b3(a+b)(a2+2ab+b23ab)=a3+b3(a+b)(a2ab+b2)=a3+b3a3+b3=(a+b)(a2ab+b2)

 

laugh

.
 Sep 17, 2015
 #1
avatar+26396 
+5
Best Answer

a3+b3= ?

 

 

 

(a+b)3=a3+3a2b+3ab2+b3(a+b)33a2b3ab2=a3+b3(a+b)33ab(a+b)=a3+b3(a+b)[(a+b)23ab]=a3+b3(a+b)(a2+2ab+b23ab)=a3+b3(a+b)(a2ab+b2)=a3+b3a3+b3=(a+b)(a2ab+b2)

 

laugh

heureka Sep 17, 2015

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