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a=13 b=18 c=26 what are the missing angles of the triangle

 May 27, 2015

Best Answer 

 #1
avatar+3146 
+8

http://en.wikipedia.org/wiki/Law_of_cosines

a=13 b=18 c=26
cos Alpha = (b2 + c2 - a2) / (2*b*c)
cos Beta = (c2 + a2 - b2)/(2*c*a)
Gamma=180-Alpha-Beta

a=13; b=18; c=26; acos((b^2 + c^2 - a^2) / (2*b*c)) = 27.399361586368°

a=13; b=18; c=26; acos((c^2 + a^2 - b^2)/(2*c*a)) = 39.582305569896°

180 - 27.399361586368 - 39.582305569896= 113.018332843736°

verification with http://en.wikipedia.org/wiki/Law_of_sines

13sin360(27.399361586368)=28.249208025435121118sin360(39.582305569896)=28.249208025418069526sin360(113.018332843736)=28.2492080254044281

 May 27, 2015
 #1
avatar+3146 
+8
Best Answer

http://en.wikipedia.org/wiki/Law_of_cosines

a=13 b=18 c=26
cos Alpha = (b2 + c2 - a2) / (2*b*c)
cos Beta = (c2 + a2 - b2)/(2*c*a)
Gamma=180-Alpha-Beta

a=13; b=18; c=26; acos((b^2 + c^2 - a^2) / (2*b*c)) = 27.399361586368°

a=13; b=18; c=26; acos((c^2 + a^2 - b^2)/(2*c*a)) = 39.582305569896°

180 - 27.399361586368 - 39.582305569896= 113.018332843736°

verification with http://en.wikipedia.org/wiki/Law_of_sines

13sin360(27.399361586368)=28.249208025435121118sin360(39.582305569896)=28.249208025418069526sin360(113.018332843736)=28.2492080254044281

admin May 27, 2015

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