40x+10x^2=o ? what i did was divide it by 10 so it became 4x + x^2=0
Then moved 4x to the otherside so it becamse x^2 = -4x then the square root of that? Is this a solution or am i doing wrong?
\small{\text{$ \begin{array}{rcl} 40x+10x^2 &=& 0 \\\\ \underbrace{ \textcolor[rgb]{150,0,0}{\mathbf{10x}} }_{=0}\cdot ( \underbrace{ \textcolor[rgb]{0,0,150}{\mathbf{4+x}} }_{=0} ) &=& \mathbf{ 0 } \\\\ \end{array} $}}\\\\ \textcolor[rgb]{150,0,0}{\mathbf{10x}} = 0 \qquad | \qquad : 10 \\ \boxed{ \textcolor[rgb]{150,0,0}{\mathbf{x}} = 0}\\\\ \textcolor[rgb]{0,0,150}{\mathbf{4+x}} = 0 \qquad | \qquad -4 \\ \boxed{ \textcolor[rgb]{0,0,150}{\mathbf{x}} = -4}