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40x+10x^2=o ? what i did was divide it by 10 so it became 4x + x^2=0 

Then moved 4x to the otherside so it becamse x^2 = -4x then the square root of that? Is this a solution or am i doing wrong?

 May 13, 2015

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 #1
avatar+26397 
+5

40x+10x^2=o ?

\small{\text{$ \begin{array}{rcl} 40x+10x^2 &=& 0 \\\\ \underbrace{ \textcolor[rgb]{150,0,0}{\mathbf{10x}} }_{=0}\cdot ( \underbrace{ \textcolor[rgb]{0,0,150}{\mathbf{4+x}} }_{=0} ) &=& \mathbf{ 0 } \\\\ \end{array} $}}\\\\ \textcolor[rgb]{150,0,0}{\mathbf{10x}} = 0 \qquad | \qquad : 10 \\ \boxed{ \textcolor[rgb]{150,0,0}{\mathbf{x}} = 0}\\\\ \textcolor[rgb]{0,0,150}{\mathbf{4+x}} = 0 \qquad | \qquad -4 \\ \boxed{ \textcolor[rgb]{0,0,150}{\mathbf{x}} = -4}

 May 13, 2015
 #1
avatar+26397 
+5
Best Answer

40x+10x^2=o ?

heureka May 13, 2015

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