2x+3y=1 and -3x+y=15 how do you get points (-4,3)
(1)2x+3y=1(2)−3x+y=15|∗3(2)−9x+3y=45$$ (1)−(2):2x−(−9x)+3y−3y=1−4511x=−44x=−4(1)2(−4)+3y=1−8+3y=13y=9|:3y=3