Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
788
1
avatar

2(x^3y^5)^2

 Apr 21, 2014

Best Answer 

 #1
avatar+130474 
+5

2(x3y5)2  

Remember that we have a rule of powers (exponents) that says (am)n = a(m*n)

In effect, we're multiplying the "inside" power by the "outside" power

So we really have      2[ (x3)2 * (y5)2 ] = 2[x6 * y10] = 2x6y10

 Apr 21, 2014
 #1
avatar+130474 
+5
Best Answer

2(x3y5)2  

Remember that we have a rule of powers (exponents) that says (am)n = a(m*n)

In effect, we're multiplying the "inside" power by the "outside" power

So we really have      2[ (x3)2 * (y5)2 ] = 2[x6 * y10] = 2x6y10

CPhill Apr 21, 2014

2 Online Users

avatar