A six-sided die (with numbers 1 through 6) and an eight-sided die (with numbers 1 through 8) are rolled. What is the probability that there is exactly one 6 showing? Express your answer as a common fraction.
1/6 for the first die
1/8 for the second die
1/48, the probability that BOTH will roll a 6.
1/6 + 1/8 - 1/48?
+171 No,
\(1\over6\) for the 6-sided die
\(1\over8\) for the 8-sided die
\(1\over{6}\)+\(1\over8\)=\(7\over24\)
\(\frac{1}{6}\cdot\frac{7}{8}=\frac{7}{48}\)
1/6 for the probability of rolling a 6, 7/8 is the probability of not rolling a 6.
\(\frac{1}{8}\cdot\frac{5}{6}=\frac{5}{48}\)
1/8 for the probability of rolling a 6, 5/6 is the probability of not rolling a 6.
\(\frac{7}{48}+\frac{5}{48}=\frac{12}{48}=\frac{1}{4}\)
Add the probabilities together.
