Think about this:
This is 4 lots of A plus X lots of A
so when you factored it you will have A(4+X) or (4+X) *A
your question is the same.
This is 4 lots of (x+3) plus x lots of (x+3)
when you put it together you have (4+x) lots of (x+3) which is just (4+x)(x+3)
this woul normally be reorganised as
It is nice to see you.
That is what I thought but it could be that the 6 was meant to be a 7 in which case it would still be half.
or that we were suppose to include the possibility of a tie, whch would make the problem a tad harder.
Say we were meant to include the possibility of a tie.
Then the outcomes culd be 2:4, 4:2, or 3:3
I do not think it could be 1:5 or 0:6 because then the series would have finished earlier.
The number of ways a team can win 2 games in 6 is 6C2 = 15
The number of ways a team can win 3 games in 6 is 6C3 = 20
The number of ways a team can win 4 games in 6 is 6C4 = 15
So the probability that they score 3 games each is 20/50 = 4/10
The remaining possibilities are split equally between A and B wining 0.5(1-0.4) = 0.3
So if they play 6 games the probabilities are
P(tie) = 0.4
P(A wins) = P(Bwins) = 0.3