The denominator of a fraction is 2 more than its numerator.
When 1/2 is added to this fraction, the resulting fraction's denominator is twice the denominator of the original fraction and its numerator is 1 more than its denominator.
What is the numerator of the original fraction?
3
5
8
11
My answer='A'
What is the exact solution to the equation e^3x+5=9?
x=3/5+ln9
x=3/ln9-5
x=5+ln9/3
x=ln9-5/3
My answer='C'
+128633 The denominator of a fraction is 2 more than its numerator.
When 1/2 is added to this fraction, the resulting fraction's denominator is twice the denominator of the original fraction and its numerator is 1 more than its denominator.
What is the numerator of the original fraction?
We have
x / [ x + 2 ] + 1/2 = [ 2 (x + 2) + 1 ] / [ 2(x + 2) ]
Simplify
[ 2x + x + 2 ] / [2 (x + 2] = [ 2x + 5 ] / [ 2(x + 2) ]
Multiply through by 2(x + 2)
2x + x + 2 = 2x + 5
3x + 2 = 2x + 5
x = 3 ⇒ "A" is correct !!!!
I think this is.....
e^(3x+5) = 9 take the Ln of both sides
Ln e^(3x + 5) = Ln 9
(3x + 5) Ln e = Ln 9 ⇒ { Ln e = 1}
3x + 5 = Ln 9 subtract 5 from both sides
3x = Ln (9) - 5 divide both sides by 3
x = [ Ln (9) - 5 ] / 3 ......the last answer is correct....if I've interpreted this correctly
